When Xiaoliang did the experiment of measuring "rated power of small light bulb", the equipment used included power supply with voltage of 6V, small light bulb with rated voltage of 2.5V (rated power of small light bulb is less than 1W), sliding rheostat (50 Ω 1a), and ammeter, switch and wire meeting the experimental requirements. As shown in figure (a), Xiaoliang did not connect the complete circuit

When Xiaoliang did the experiment of measuring "rated power of small light bulb", the equipment used included power supply with voltage of 6V, small light bulb with rated voltage of 2.5V (rated power of small light bulb is less than 1W), sliding rheostat (50 Ω 1a), and ammeter, switch and wire meeting the experimental requirements. As shown in figure (a), Xiaoliang did not connect the complete circuit

What about Tu? How to do without Tu

There are two dry batteries in the power supply, and the resistance of the small bulb is 14 ohm. When the power is on, the voltage at both ends of the small bulb is 2.8V?

First find the current flowing through the circuit: I = V / R
I=2.8/14=0.2(A)
Because the current flowing through the series circuit is the same, the battery voltage is 3 V, and the voltage measured after power on is 2.8 V, that is, the voltage drops on the internal resistance of the battery, 3-2.8 = 0.2 (V)
Internal resistance of battery: r = V / I = 0.2 / 0.2 = 1 (Ohm)
A: in a series circuit, the internal resistance of the battery is 1 ohm

As shown in the figure is the experiment of measuring "rated power of small bulb" (the small bulb is marked with "2.5V")___ Table B should be___ (2) please replace the wire with a stroke line, and complete the wire between the two according to the circuit diagram of figure a; (the original wire is not allowed to be changed, and the wire is not allowed to be handed over; (3) if the wire is well connected, when the switch is closed, the small light bulb lights up and goes out suddenly, what may be the cause of this phenomenon? (answer a reason) (4) after troubleshooting, it is found that the voltage indication is 2V in the experiment. In order to measure the rated power, slide the slide of sliding rheostat to p direction___ (5) when the small bulb lights up normally, the ammeter shows the number as shown in Figure C in the figure, and the current passing through the small bulb is___ A. What is the rating of a small bulb___ W．

(1) According to the fact that the voltmeter should be connected in parallel with the tested electrical appliance and the ammeter should be connected in series in the circuit, a represents the ammeter and B represents the voltmeter. (2) the rated voltage of the bulb is 2.5V, so the battery should be selected as the power supply, the range of the voltmeter should be 0-3v, and it should be connected in parallel with the bulb, and the current flows from the positive terminal to the negative terminal

Brightness of small bulbs with different rated voltage and same rated power
Is it the same

If the power is supplied by each rated voltage, the brightness of small bulbs with the same rated power is the same; if the power is supplied by the same voltage, the brightness of small bulbs with lower rated voltage is higher