The electromotive force of the power supply is 3V, and the internal resistance is 0.2 Ω. When the external circuit is open, the current and terminal voltage in the circuit are

The electromotive force of the power supply is 3V, and the internal resistance is 0.2 Ω. When the external circuit is open, the current and terminal voltage in the circuit are

If the circuit is open, the current in the circuit is zero theoretically. The terminal voltage is the electromotive force 3V

Electromotive force E = 3V, internal resistance R = 0.1 Ω, external circuit resistance R = 1.4 Ω in the closed circuit, calculate the current I and terminal voltage u in the circuit
In the closed circuit, the electromotive force of the power supply e = 3V, the internal resistance R = 0.1 Ω, and the resistance of the external circuit R = 1.4 Ω

The current in the circuit I = E / (R + R) = 3 / (1.4 + 0.1) = 2A
Terminal voltage U = E-IR = 3-2 × 0.1 = 2.8V

3. If the electromotive force of the power supply is 3V, the internal resistance is 0.2 Ω, and the external circuit resistance is 1.8 Ω, the current in the circuit is______ The terminal voltage is_______ .

1.5A
1.8*1.5=2.7v

The electric force of the power supply is 3V, the internal resistance is 0.2 ohm, and the resistance of the external circuit is 1.3 ohm

According to e = I (R + R), it is concluded that:
Current I = E / (R + R) = 3 / (0.2 + 1.3) a = 2A
Because e = u inside + U outside
So u out = E-U in
Outside u = E-IR = 3-2 * 0.2V = 2.6V