What is the total resistance when R1 = 3 Ω and R2 = 6 Ω are connected into the same circuit

What is the total resistance when R1 = 3 Ω and R2 = 6 Ω are connected into the same circuit


Series connection: r = R1 + R2 = 3 + 6 = 9 Ω
Parallel: 1 / (1 / 3 + 1 / 6) = 2 Ω



The resistance of 1 ohm and 1000 ohm in parallel is R1, 1 ohm, and the resistance of 1000 ohm and 10000 ohm in parallel is R2
The resistance of 2 ohm and 100 ohm in parallel is R3. The resistance of 1 ohm and 10000 ohm in parallel is R4. The order of R1, R2, R3 and R4 from large to small is as follows____ .


R3>R4>R1>R2
Please accept



In the circuit shown in the figure, R1 = 8 Ω, R2 is sliding rheostat, and the power supply voltage is 6V. Adjust the rheostat to make the voltage constant
In the circuit shown in the figure, R1 = 8 Ω, R2 is sliding rheostat, and the power supply voltage is 6V
When adjusting the rheostat so that the voltage indication is 4V, what is the resistance of the rheostat R2 connected to the circuit?


1. If the voltmeter shows the voltage at both ends of R1, the voltage at both ends of R2 is 6-4 = 2V,
R 1 / R 2 = 8 / R 2 = 4 V / 2 v = 2, R 2 = 4 Ω
2. If the voltmeter shows the voltage at both ends of R2, the voltage at both ends of R1 is 6-4 = 2V,
R1 / r2 = 8 / r2 = 2V / 4V = 1 / 2, R2 = 16 Ω



Resistor R1 and R2 are marked with "15 Ω 1A" and "10 Ω 1.2A" respectively. It is necessary to connect them in series with the maximum voltage in the circuit


In series, the current is equal, so the maximum current cannot exceed 1a, so the maximum voltage is 1A * (15 + 10) = 25V