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It is known that a circuit has two series resistors R1 and R2, where R1 = 1 Ω and R2 = 2 Ω are powered by two dry batteries with a voltage of 1.5V, then the current flowing through the circuit
Total voltage of two batteries:
U=1.5x2=3v
Total resistance:
R total = R1 + R2 = 3 Ω
According to Ohm's Law:
I = u total / R total = 3 / 3 = 1A
There are two resistors R1 and R2, R1 = 10 ohm and R2 = 15 ohm. Connect them in parallel to both ends of the battery pack and close the switch
Then the voltage ratio between R1 and R2 is_______ The ratio of current intensity through R1 and R2 is________
The ratio of voltage is 1:1, and the ratio of current intensity is U / 10: U / 15,
(1) The parallel circuit voltage is equal
So the ratio of R1 to R2 is 1:1
(2) Through R1 current I1 = u / r = u / 10 Ω
Through R2 current I2 = u / r = u / 15 Ω
I1：I2=（U／10)：（U／15）
The numerator and denominator are the same to divide a non-zero real value
So I1: I2 = 3:2
There are two resistors R1 and R2, R1 = 10 ohm and R2 = 15 ohm. Connect them to both ends of the battery pack in parallel and close the switch_
Then the voltage ratio between R1 and R2 is_______ The ratio of current intensity through R1 and R2 is________
Write the reason
Because parallel shunt has no partial pressure, U1: U2 = 1:1
According to Ohm's law, I = u / R, the voltage is the same, and the current is inversely proportional to the resistance
In the circuit as shown in the figure, the resistance R1 = 8ohm, R2 = 10ohm, the supply voltage and the resistance of the setting resistance R are unknown,
I2=0.2*(R+8)/(R+10)
When R is infinite, R + 8 and R + 10 are very close to R, that is, R + 8 = R, R + 10 = R, so the above formula becomes: I2 = 0.2 * r / r = 0.2 * 1 = 0.2
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