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When the mass ratio of R to oxygen is 3:2, the relative atomic mass of R is 0
Because it has + 2 valence, its oxide is RO, and the molecular weight of O is 16, so r is 24, Mg
If the mass ratio of metal element and oxygen is 9:8, the relative atomic mass of a metal element with + 3 valence is less than 5?
The mass of oxygen contained in 20.4g of this oxide is equivalent to the mass of oxygen contained in Fe3O4
Suppose that the chemical formula of the oxide is M2O3, the mass of oxygen is 48, so the mass of metal is 54, and the mass of one m is 27
The mass of Fe3O4 is (56 × 3 + 64) × 0.15 = 36.3g
In a divalent metal oxide, when the mass ratio of metal element to oxygen is 5:2, the relative molecular weight of the metal oxide is?
Oxygen is 16, because it is divalent, so the number ratio of metal atoms to oxygen atoms is 1:1
So the unknown metal element is 40
The relative atomic mass of Ca is just 40
So it's Cao
The relative molecular weight is 56
In a 2-valent metallized oxide, if the mass ratio of metal to oxygen is 3:2, what is the relative molecular mass of the oxide
MO
x：16====3：2
x=24
MO：24
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