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When measuring the density of salt water, they measured that the mass of salt water was 105g, the volume of salt water was 100ml, and the known density of salt was 2700kg / m3, Calculate the salt content t of this brine (the mass of salt in each cubic meter of brine)
If the density of the brine is 1.05 × 10 & sup3; kg / M & sup3;, then the mass of 1 cubic meter of the brine is 1050kg. Suppose the mass of salt in 1 cubic meter of the brine is t, then the mass of water is 1050-t, then the volume of water is (1050-t) × 1000, the volume of salt with mass of T is t △ 2700 plus water
Given the density of salt water, the density of salt water, the volume of salt water, how to calculate the salt content?
Premise: salt dissolved in water will not lead to volume increase, that is, V salt water = V water; P salt water = m salt water / V salt water = m salt water / V water = (M Salt + m water) / V water = (P water V water + P salt V salt) / v = P water + P salt V salt / V water, so p salt V salt / V water = P salt water - P water - - - - - - - - - (1) salt content = m salt / M salt
The mass of salt is 5g, the volume of water is 60cm, the volume of brine is 65cm, and the density of brine is? Kg / m;
Give me an answer in 96 hours
Brine density
(60+5)÷65=1g/cm^3
=1/1000kg/(1/1000^2)m^3
=1000kg/m^3
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