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The buoyancy of a wood block with a mass of 1kg and a density of 0.4 × 103kg / m3 is () A. 1kgB. 5kgC. 9.8ND. 24.5N
G wood = m wood, g = 1kg × 9.8n/kg = 9.8N, because ρ wood < ρ water, the wood block is floating when it is still in water; F floating when the wood block is floating = g wood = 9.8N
A piece of ice floats on the surface of the water, the volume of which is 100cm3. The known density of ice is 0.9 × 103kg / m3. How much is this piece of ice
Let v be the volume of ice, ρ be the density of water, ρ'mg = f, floating (ρ V) g = ρ'g (v-0.0001) 0.9 × 10 & sup3; v = 1 × 10 & sup3; (v-0.0001) v = 1 × 10 ^ (- 3) M & sup3; mass m = ρ, v = 0.9 × 10 & sup3; × 1 × 10 ^ (- 3) kg = 0.9kg; weight g = mg = 0.9 × 9.8 = 8.82n
A wooden block with a density of 0.6 × 103kg / m3 and a volume of 100cm3 is tied to the bottom of the container with a string, as shown in the figure
Just make the horizontal plane level with the upper surface of the block. What is the tension on the rope at this time? G is 10N / kg
F = 1n, g = mg = 0.6N, the object floats, and the rope receives 0n pull force, which seems to be the case
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