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When a is put into alcohol (ρ = 0.8 × 103kg / m3) and B is put into water at rest, the ratio of buoyancy is 3:2, then the density of B is () A. 0.6×103kg/m3B. 0.8×103kg/m3C. 1.2×103kg/m3D. 1.5×103kg/m3
The mass of a and B objects is equal, the density ratio ρ A: ρ B = 1:2, from the density deformation formula v = m ρ, it can be seen that V A: v b = 2:1; ① if a and B are floating, then the buoyancy ratio is 1:1, which does not meet the conditions, and there is no such state; ② if a and B are immersed (suspended or sinking), V row = V objects, then the buoyancy ratio f a: F B = ρ & nbsp; V A G ρ & nbsp; V B G & nbsp; =8 × 2 × G1 × 1 × g = 8:5, does not meet the conditions, there is no such state; ③ if a floats on the alcohol surface, the buoyancy received by a is equal to the weight of the object; if B is immersed (suspended or sinking), the buoyancy received by B is less than or equal to the weight of the object, so the buoyancy received by B is less than or equal to the buoyancy received by a, the ratio of buoyancy received is 3:2, meets the conditions, there is such state: a floats On the alcohol surface, f a = mg = ρ a V A G; B immersion, F B = ρ water v b g; ∵ f a: F B = ρ a V A G ρ water v b g = ρ a × 2 × & nbsp; G ρ water × 1 & nbsp; (4) if a is submerged (floating or sinking), the buoyancy of a is less than or equal to the weight of the object; if B is floating on the water surface, the buoyancy of B is equal to the weight of the object, so the buoyancy of a is less than or equal to the buoyancy of B, and the ratio of buoyancy is 3:2, which is inconsistent If the condition is satisfied, there is no such state
When a solid ball with a density of 0.9 × 103kg / m3 is put into water and alcohol successively, the ratio of the volume of water discharged from the ball to the volume of alcohol discharged from the ball is________ What is the buoyancy ratio of the ball in water and alcohol______ (ρ = 0.8 × l03kg / m3)
There are some on Baidu, but I can't understand them,
When a solid ball with a density of 0.9 × 103kg / m3 is put into water and alcohol successively, the ratio of the volume of water discharged by the ball to the volume of alcohol discharged by the ball is (4:5); the ratio of buoyancy of the ball in water and alcohol is (1:1); (ρ liquor = 0.8 × 103kg / m3) according to the density of the solid ball is 0.9 × 103kg / m3
Calculate the volume of alcohol with mass of 100g and density of 0.8 × 103kg / m3?
Tonight's homework is due tomorrow~
Format: according to the known, ask, answer to write
It is known that: density p = 0.8 × 10 & # 179; kg / M & # 179;, mass m = 100g =; the volume of alcohol v
From the formula of density p = mass m ﹥ volume V, v = m ﹥ P = 0.1kg / (0.8 × 10 ﹥ kg / m ﹥ 179;) = 0.125 × 10 ﹥ m ﹥ 179;
A: the volume of the alcohol is 0.125 × 10 - (?) 179; m - (?) 179
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