The voltage at both ends of a circuit is 220 V, and the resistance of the consumer is 40 Ω. Can we use an ammeter with a range of 0 ~ 3a to measure its current?
According to Ohm's law, the current passing through the bulb is I = ur = 220v40 Ω = 5.5A; obviously, the current passing through the bulb exceeds the range of the ammeter, so the current in the circuit can't be measured by the ammeter with the range of 0 ~ 3a. A: the current in the circuit can't be measured by the ammeter with the range of 0 ~ 3a
How to change the ammeter when one consumer is reduced in parallel circuit?
When a consumer is reduced, the resistance of the whole circuit will increase, and the ammeter connected to the bus will decrease
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