After absorbing 1000j of heat from the outside, an object can do 650j of work, and the internal energy of the object can be calculated_____ (fill in "increase" or "decrease")____ J.

After absorbing 1000j of heat from the outside, an object can do 650j of work, and the internal energy of the object can be calculated_____ (fill in "increase" or "decrease")____ J.

Increase, 350

The work done on the compressed gas is 1350 coke, and the gas releases 650 coke of heat to the outside world. How much Coke does the internal energy of the compressed gas increase or decrease

(1350-650 =) 700 joules were added
When work is done on an object, its internal energy increases; when work is done on an object, its internal energy decreases

When the gas expands, it does 100J of external work and absorbs 120J of heat from the outside. The change of its internal energy may be ()
A. Reduced 20jb. Increased 20jc. Decreased 220jd. Increased 220j

According to the first law of thermodynamics, △ u = w + q = - 100J + 120J = 20j, then the internal energy of gas increases by 20j

A certain amount of gas absorbs 1676j of heat from the outside, and the internal energy increases by 476j?

W+Q=ΔE
W=476-1676=-1200J
Negative means that the external work of gas is 1200J