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When an electric stove is connected to a 220 V circuit, it takes 5 minutes to boil a pot of water. Then, when it is connected to a 110 V circuit (other conditions remain unchanged), the time required to boil such a pot of water is () A. 20minB. 15minC. 10minD. 5min
In the process of using electric furnace, all electric energy is converted into heat energy, and the heat generated is equal to the work done by the current. According to the analysis of W = u2rt, let the resistance be r, which is obtained by w = u2rt, & nbsp; u21rt1 = u22rt2, the resistance of the same electric furnace is equal, and R is reduced and substituted into the data to get, (220V) 2 × 5min = (110V) 2t2, then T2 = 20min; therefore, select a
When the electric furnace of 220v1000w is connected to the 110V power supply, how to calculate the actual power consumption of the electric furnace
First, calculate the load resistance: I = P / u = 1000 / 220 = 4.55 (a), r = u / I = 220 / 4.55 = 48 (Ω). Calculate the power at 110V: I = u / r = 110 / 48 = 2.3 (a), P = UI = 110 * 2.3 = 253 (W), and the power at 110V is only 253w
A "220v1000w" electric furnace, want to refit it to 110V power supply, but the electric power still needs to maintain 1000W, how to install? Please connect% B
A "220v1000w" electric furnace wants to be refitted and connected to 110V power supply, but the electric power still needs to maintain 1000W. How should it be installed? Please explain the reason through calculation
As long as the resistance wire is divided into two equal halves and connected in parallel to 110 V, the formula is: power = square of voltage / resistance, the resistance at 220 V and 110 V are 48.4 Ω and 12.1 Ω respectively, and the resistance wire divided into two halves and connected in parallel is exactly equal to 12.1 Ω
An electric furnace is marked with the word "220 V 800 W". It is connected to the circuit of 220 V, and the
The circuit consumed by 1 hour of power on
2. How much heat is released by the electric furnace after one hour of power on?
3. If the circuit is powered on for 8 hours a day, how much power will be consumed in one month (30 days)?
How many hours can 4 1kW. H electric energy be used for this furnace?
1 800/1000kW×1=0.8kWh
2 0.8kWh=2880000J
3 0.8kW ×8h× 30=192kWh
4 1kWh÷ 0.8kWh=1.25h
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