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The power supply voltage is constant, R1 = 6ohm, R2 = 12ohm, sliding rheostat R3 = maximum resistance value 0, ammeter range is 0 ~ 0.6A, voltmeter range is 0 ~ 3V, open S1, close S2, the heat generated by current through R1 within 10 seconds is 60 joules, power supply voltage is u =? Sliding rheostat R3 = maximum resistance 20 ohm
Please give me a picture
2. What is the resistance value of R3
3. Give it in the form of questioning, then I can find it immediately
Power supply voltage U = 24 V, resistance R1 = 6 Ω, rheostat R2 resistance range of 0-100 Ω, ammeter range of 0-3 a, voltmeter range of 0-15 v
(2) the maximum power allowed by the circuit. (the voltmeter measures the resistance of R2, which is connected in series with R1
(1) When I = 3A, R2 voltage = 24-3 * R1 = 6V, R2 = 6 / 3 = 2 Ω; when u = 15V, R2 current = (24-15) / R1 = 1.5A, R2 = 15 / 1.5 = 10 Ω; so R2 value range is 2-10 Ω
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