The maximum speed of the vehicle with rated power of 80kW can reach 20m / s on the horizontal highway, and the vehicle mass is 2T The results are as follows: 1. How much resistance does the car suffer; 2. How much instantaneous power does the car have at the end of the second and third seconds; 3. How long can the car maintain the process of uniform acceleration; 4. How much work does the car's traction force do in the process of uniform acceleration

The maximum speed of the vehicle with rated power of 80kW can reach 20m / s on the horizontal highway, and the vehicle mass is 2T The results are as follows: 1. How much resistance does the car suffer; 2. How much instantaneous power does the car have at the end of the second and third seconds; 3. How long can the car maintain the process of uniform acceleration; 4. How much work does the car's traction force do in the process of uniform acceleration

1: F resistance = f traction = P / VM = 4kn
2: F = ma = 4kn
F pull = f close + F resistance = 8kN
V3=at=6m/s
P = f, V3 = 48kW
3:t=Vm/a=10s
4:S=Vm/a=10s
W pull = w close + W resistance = 1 / 2mvm2 + F resistance s =

In other words, who can tell me what power P = w / T is equal to

In Mechanics:
P = W/t =FVcosa
When f and V are in the same direction, P = FV
In electricity: P = w / T = u ^ 2 / r = I ^ 2R = UI