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When the slider slides on the conveyor belt faster than the conveyor belt and can slide out of the conveyor belt, the work done by friction is equal to the product of friction and the length of the conveyor belt, so the reduction of kinetic energy of the slider is equal to the work done by friction. However, the heat generated by the system is the product of friction and the relative displacement of the slider and the conveyor belt, But at this time, the relative displacement and the length of the conveyor belt are not equal. So the formula listed according to the conservation of energy and the formula listed by the kinetic energy theorem are different. So in the conservation of energy formula, do I not list that energy? Besides the work done by friction, what is the energy conversion on the conveyor belt? What are the test points about the conveyor belt? The work done by friction and the object sliding on the conveyor belt What is the relationship between the initial velocity of the belt time? The slider is horizontal
If you want to analyze the problem from the conservation of energy, it is not troublesome. The total work done by the conveyor belt is nothing more than the reduction of the kinetic energy of the object and the internal energy generated by friction. It is easy to find the reduction of kinetic energy, or the direct f * s internal energy, as long as you know the relative displacement
What is the work done by the conveyor belt to the object, by the object to the conveyor belt, and by the motor
First of all, the conveyor belt has friction and support on the force of the object. The support does not work because there is no displacement
The work done by friction will be calculated, right? Force x displacement
The object has no displacement to the gravity of the conveyor belt, which is decomposed into friction and pressure perpendicular to the conveyor belt, and does no work
The work done by the motor depends on the motor itself. There are not all formulas for power
What's the difference between the work done by a conveyor belt on an object and the work done by a conveyor belt to overcome the friction of an object on it
When calculating kinematics problems, we use relative displacement, such as a block sliding on rough horizontal ground. When we look at work, when the object moves on the conveyor belt from static to the same speed as the conveyor belt, when we study how much work the conveyor belt does to the object, we first make it clear that the work done by the conveyor belt to the object is transformed into
An object with a mass of 2kg is placed on a 1 meter per second conveyor belt without speed. The conveyor belt is long enough. How much power is consumed in this process
Object acceleration displacement on conveyor belt X1 = VT / 2 conveyor belt movement distance x2 = VT relative displacement x2-x1 = VT / 2
Power consumption FX2 = 2fx1 = 2 * 1 / 2mV ^ 2 = MV ^ 2
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