It is known that the perimeter of a triangle is 2x & # 178; cm, and the lengths of its two sides are (2x + 1) cm, (X & # 178; - 2x + 1) cm Given that the perimeter of a triangle is 2x & # 178; cm, and that the lengths of its two sides are (2x + 1) cm, (X & # 178; - 2x + 1) cm, what is the length of the third side of the triangle?

It is known that the perimeter of a triangle is 2x & # 178; cm, and the lengths of its two sides are (2x + 1) cm, (X & # 178; - 2x + 1) cm Given that the perimeter of a triangle is 2x & # 178; cm, and that the lengths of its two sides are (2x + 1) cm, (X & # 178; - 2x + 1) cm, what is the length of the third side of the triangle?


Third side = 2x & # 178; - 2x-1-x & # 178; + 2x-1
=X & # 178; - 2 (CM)
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It is known that the lengths of two sides of a triangle are 7cm and 1cm respectively, and the third side of the triangle is an integer
(detailed answer process, not a single answer)


The sum of the two sides of the triangle is greater than the third side, and the difference between the two sides is less than the third side
(7-1) < X < (7+1)
6 < X < 8
The third side is an integer, no more than 7
So the perimeter is 7 + 7 + 1 = 15