Fill a cylindrical bucket with a diameter of 40 cm and a height of 60 cm full of water into another cylindrical bucket with a radius of 30 cm, and then ask what the water is What's the height? We need to solve the equation of first degree with one variable

Fill a cylindrical bucket with a diameter of 40 cm and a height of 60 cm full of water into another cylindrical bucket with a radius of 30 cm, and then ask what the water is What's the height? We need to solve the equation of first degree with one variable

π*20^2*60=π*30^2*h
h=24000/900
h=80/3

Fill a cylindrical bucket with a diameter of 40 cm and a height of 60 cm full of water into another cylindrical bucket with a radius of 30 cm, and then ask what the water is
What's the height

Pai (PI) * 20 * 20 * 60 = Pai * 15 * 15 * h
h=320/3

1. A bucket with a bottom diameter of 40 cm and a height of 60 cm contains 30 cm of water. After a watermelon is completely submerged in the water, the water surface rises by 10 cm

Idea: increase the volume of water is the volume of watermelon
Radius: 40 △ 2 = 20 (CM)
Bottom area: 3.14 × 20 × 20 = 1256 (cm2)
Volume of water in ascending part: 1256 × 10 = 1256 (cm3)
Complex methods
The volume of water now - the volume of the original water
1256 × (30 + 10) - 1256 × 30 = 1256 (cm3)