The speed of a, B and C is 30 meters, 40 meters and 50 meters per minute respectively. A and B set out in the same direction at the same time in a, C set out from B to catch up with a and B at the same time, and C took 10 minutes to catch up with B after catching up with a, then the distance between AB and B is______ .
10 × (50-40) / (40-30) × (50-30), = 10 × 10 / 10 × 20, = 100 / 10 × 20, = 10 × 20, = 200 (meters); answer: the distance between AB and ab is 200 meters. So the answer is: 200
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