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When a 2000 kg vehicle runs on a horizontal highway with a rated power of 60000w, the resistance of the vehicle is always 2000 n Find (1) the maximum speed that a car can reach (2) The speed of the car is 20m / s at a certain time, and the acceleration at this time is calculated
From P = FV = FVM VM = P / F = 30m / S
The maximum speed that a car can reach is 30 m / s
The vehicle speed is 20m / s, f = P / v = 3000n
F-f=ma a=0.5m/s^2
At a certain time, the speed of the car is 20m / s, and the acceleration a = 0.5m/s ^ 2
Someone pushes a car westward with a force of 20n in the horizontal direction. What is the resistance to the car______ N. The direction is______ ．
The car moves to the west at a constant speed in the horizontal direction. The object is pulled to the west by the balance force in the horizontal direction, with the size of 20n. According to the balance condition of the two forces, the resistance of the car is horizontally eastward, with the size of 20n. So the answer is: 20; horizontally eastward
Someone pushes a car westward with a force of 20n in the horizontal direction. What is the resistance to the car______ N. The direction is______ ．
The car moves to the west at a constant speed in the horizontal direction. The object is pulled to the west by the balance force in the horizontal direction, with the size of 20n. According to the balance condition of the two forces, the resistance of the car is horizontally eastward, with the size of 20n. So the answer is: 20; horizontally eastward
(car) 1kgm =? NM
1kg = 1kg * 9.8N = 9.8N, so 1kgm = 9.8nm
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