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The distance between station a and station B is 96 km. The express train and the local train leave from station a at the same time. It is known that the express train is 12 km faster than the local train per hour, The distance between station a and station B is 96 km. The express train and the local train depart from station a at the same time. It is known that the express train is 12 km faster than the local train per hour. If the express train arrives at station B 40 minutes earlier than the local train, the speed of the express train and the local train should be calculated
Suppose the local speed is x and the express speed is x + 12
96/(X+12) — 96/X = 40/60
The solution is x = 36 km / h, and the express speed is 48 km / h
The distance between station a and station B is 408 kilometers. A slow train runs from station a for 72 kilometers per hour, and an express train runs from station B for 96 kilometers per hour
1. The two cars are going backwards at the same time, and after a few hours, they are 660 kilometers apart
2. The two trains are facing each other. The local train starts for one hour, and the express train starts for a few hours before they meet
3. The two trains are going in the same direction at the same time (the local train is ahead), and after a few hours, the distance between the express train and the local train is 60 km
Can you use the equation to make it clear? Thank you
The express train starts from station a at a speed of 100 km / h, and the slow train starts from station a at a speed of 100 km / h
The speed of the express train is 100 km / h from station a, the speed of the slow train is 100 km / h from station a, and the speed of the express train is 140 km / h from station B
Q: the two trains leave at the same time and travel in the same direction. The local train is ahead. How long after the two trains leave, the express train catches up with the local train?
Please help me
The distance between station a and station B is 400 km. The slow train starts from station a at a speed of 100 km / h, and the fast train starts from station B at a speed of 140 km / h
Q: the two trains leave at the same time, go in the same direction, and the slow train is ahead. How long after the two trains start, the fast train will catch up with the slow train? It's better to draw a line diagram!
please hrlp me Thank you!
Chase problem: chase time = chase distance divided by chase speed difference
Let X be the pursuit time
(140-100)xx=400
40x=400
x=10
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