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The distance between Party A and Party B is 1280km, and the train speed is 3.2 times of the original speed, so it takes 11h less? What I want is the test site, not the solution to this problem
Fall in love with your smile 25,
Let's set the original speed at x kilometers per hour
1280/X－1280/3.2X＝11
1280×3.2－1280＝11×3.2X
35.2X＝816
X＝2816÷35.2
X＝80
Time from a to B after speed up: 1280 (3.2 × 80) = 5 (hours)
The distance between station a and station B is 720 km. After the train speed is increased, the running speed is 1.2 times of the original speed. The time from station a to station B is shortened by 1.2 hours?
Suppose the original speed of the train was X,
Then the speed is 1.2x
The formula is 720 / x-720 / 1.2x = 1.2
Then we can calculate x = 100
The speed of car a is 54 km / h, and that of car B is 10 m / s. if the two trains travel in the same direction for 40 seconds longer than in the opposite direction, and car a is 100 m long, the length of car B is 100 m______ ．
V a = 54km / h = 15m / s, when the two trains are running in the same direction, the speed of a relative to B is v = V A-V B = 15m / s-10m / S = 5m / s, the distance of passing train is s = L A + L B, ∵ v = st, ∵ t = SV = L A + L B 5m / S = 100m + L B 5m / S; ② when the two trains are running in the opposite direction, the speed of B relative to a is v
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