The starting price of a taxi in a city is 5 yuan within 5 km. When the distance exceeds 5 km, it will be charged at 1.2 yuan per km (less than 1 km is calculated as 1 km). Someone will pay 11 yuan to get off the taxi. How far has the taxi gone? Column inequality,

The starting price of a taxi in a city is 5 yuan within 5 km. When the distance exceeds 5 km, it will be charged at 1.2 yuan per km (less than 1 km is calculated as 1 km). Someone will pay 11 yuan to get off the taxi. How far has the taxi gone? Column inequality,

Someone's total payment = starting fee + cost over 5km
If a taxi has traveled a total of X km, then
5+（x-5）*1.2≥11-1.2 ①
5 + (X-5) * 1.2 ≤ 11 ② (system of linear inequalities with one variable)
The solution is: x > 9
x≤10．
So 9 < x ≤ 10

The starting price of a taxi in a certain city is 10 yuan. If the distance is less than 5 km, you need to pay 10 yuan. If the distance is more than 5 km, every 1 km will be increased
2 yuan (less than 1km, the increase is 1.2 yuan; the part less than 1km is calculated as 1km). Now someone takes this kind of taxi from place a to place B and pays 17.2 yuan. How much is the distance from place a to place B? (solved by inequality equation)

Set the distance to x km
10+1.2(x-5)≤17.2;
1.2(x-5)≤7.2;
x-5≤6;
x≤11;
So it's about 11 kilometers
Hope to adopt, thank you!