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When transporting cement from the station to the two construction sites, the tonnage of cement is the same. Car a transports 1.5 tons to site a each time; car B transports 2.5 tons to site B each time. At rest, car B transports 3 times less than car a, and knows that there are still 3.5 tons of cement left for site a and 4 tons left for site B, so how many tons of cement should be transported to each site
X tons per site
（x-3.5）/1.5-3=（x-4)/2.5
x=14
Two vehicles set out from the cement plant at the same time, and delivered a batch of cement to the construction site 165 km away from the cement plant. Vehicle a arrived 0.8 hours earlier than vehicle B. when vehicle a arrived, it was the first time for vehicle a to arrive
How many hours did it take for car B to drive 24 kilometers from the construction site?
According to the meaning of the title:
1. It takes 0.8 hours to drive 24 km, and its speed is 24 / 0.8 = 30 km / h
2. The driving time of vehicle a for 165 km is the same as that of vehicle B for 141 km: 141 km / 30 km / h = 47 hours
A: the whole journey took 47 hours
There are two piles of coal with a total weight of 1680 kg. After the first pile uses 3 / 4 and the second pile uses 2 / 3, the remaining coal is just equal,
How many kilos of coal did each pile have
Let the first pile of XKG and the second pile of 1680-x
(1-75%)x=(1-2/3)(1680-x)
x/4=560-x/3
x=960
1680-960=720kg
A: 960kg in the first pile and 720kg in the second pile
The total weight of two tons of coal is 1680 kg. After 75% of the first pile is used up and 2 / 3 of the second pile is used up, the remaining coal is equal. The two tons of coal used to be several thousand grams each?
Don't use equations
First batch: 1680 * (1-2 / 3) / ((1-75%) + (1-2 / 3)) = 960kg
Second pile: 1680-960 = 720kg
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