The total weight of the three piles of coal is 24 tons. If 0.5 tons are transported to the third pile from the first pile and the second pile respectively, the ton ratio of the three piles of coal is 2; 1; 3. How many tons of the three piles of coal

The total weight of the three piles of coal is 24 tons. If 0.5 tons are transported to the third pile from the first pile and the second pile respectively, the ton ratio of the three piles of coal is 2; 1; 3. How many tons of the three piles of coal

The first, second and third piles of coal are 8.5, 4.5 and 11 tons respectively

The total weight of the three piles of coal is 24 tons. If 0.5 tons are transported from the first pile and the second pile to the third pile respectively, the weight ratio of the three piles of coal is 2:1:3,
The total weight of the three piles of coal is 24 tons. If 0.5 tons are transported from the first pile and the second pile to the third pile, the weight ratio of the three piles of coal is 2:1:3
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Solution
2+3+1=6 24/6=4
The weight of the first pile after handling is 4 × 2 = 8, so the weight before handling is 8 + 0.5 = 8.5 tons
The second pile weighs 4 × 1 = 4 after handling, so the weight before handling is 4 + 0.5 = 4.5 tons
Before handling, the third pile weighs 24-8.5-4.5 = 11 tons

The three piles of coal weigh 48 tons. If one ton is transported from the first and second piles to the third pile, the mass ratio of the three piles is 2:1:5. How many tons are there in the three piles?

2+1+5=8
48 * 2 / 8 = 12 tons 48 * 1 / 8 = 6 tons 48-12-6 = 30 tons
So the first pile of 12 + 1 = 13 tons
The second pile 6 + 1 = 7 tons
The third pile 48-13-7 = 28 tons

The total weight of the three piles of coal is 30 tons. If one ton is transported from the first pile and the second pile to the third pile, the mass ratio of the three piles of coal is 2:1:3. How many tons are there in the three piles of coal?

After transporting 1 ton of the first and second coal to the third coal: the first coal: 30 × 2 / (2 + 1 + 3) = 10 (tons); the second coal: 30 × 1 / (2 + 1 + 3) = 5 (tons); the third coal: 30 × 3 / (2 + 1 + 3) = 15 (tons); the original first coal: 10 + 1 = 11 (tons); the second coal: 5 + 1 = 6 (tons); the third coal: 15-2 = 13 (tons)
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