There is a pile of coal, if you use a car to transport it all at once, you need 36; if you use B car to transport it all at once, you need 45. It is known that a car transports 1.5 tons more than B car. How many tons of this batch of coal are there in total? A simpler way to do it

The weight of vehicle B is:
(36x1.5)÷(45-36)
=54÷9
=6 (ton)
The total weight of the coal is:
45x6 = 270 (tons)

For a pile of yellow sand, it takes 45 cars to load with car a and only 36 cars to load with car B. It is known that car B can load 4 tons more than car A. how many kinds of cars can each load?

Car a 36 × 4 ÷ (45-36) = 16t
Vehicle B 16 + 4 = 20t

For one kind of oil, it takes 45 vehicles for type A and 36 vehicles for type B. It is known that there are four less vehicles for type A than for type B. how many tons of oil are there in this batch

Every problem can be wrongly written

For a pile of coal, 45 cars are loaded with car a and 36 cars are loaded with car B. It is known that car a is 40 tons less than car B. how many tons of coal is there in this pile

Each car of car a is 40 tons less than that of car B. 36 cars of car B are 40 * 36 = 1440 tons more than that of car a of the same number. These are the weight of the remaining car A. so car a didn't come. That's 1440 / (45-36) = 160, so the total weight = 160 * 45 = 7200 tons {[36 * 40] / (45-36)} * 45 = 7200 tons. This pile of coal has x tons X / 36

There is a pile of coal, if you use a car to transport it all at once, you need 36; if you use B car to transport it all at once, you need 45. It is known that a car transports 1.5 tons more than B car. How many tons of this batch of coal are there in total? A simpler way to do it