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A pile of sand weighs four tons. Two fifths of the sand was carried away in the first time. How many tons were carried away in the second time?
4 × two fifths = eight fifths (tons) eight fifths - two fifths = six fifths (tons)
Eight fifths + six fifths = fourteen fifths (tons)
A: Fourteen fifths of the tons were transported twice
A pile of coal, the first transport away more than one-fifth of its 15 tons, the second transport away one-third of the first, there are 120 tons of mathematical solution
For the second time, more than 1 / 15 of the total 5 tons were transported
So total transportation = all (1 / 5 + 1 / 15) + 20 tons
Total = (120 + 20) / (1-5 / 1-15 / 1) = 190.91 tons
A pile of coal, the first transport away 1 / 5, the second transport away 2 / 3, there are 120 tons left, how many tons of this pile of coal?
120 / (1 - 1 / 5 - 2 / 3) = 900 tons
There are 120 tons of coal in a pile. In the first time, more than 2 / 5 of the total amount of coal was transported away, while in the second time, the remaining 4 / 7 is less than 2 tons
The first 120 * (2 / 5) + 2 = 50 tons
The second time (120-50) * (4 / 7) - 2 = 38 tons
Now 120-50-38 = 32 tons
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