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When a and B start from a and B, they go in opposite directions. When they start, the speed ratio of a and B is 5:4. When they meet, a's speed decreases by 20%. In this way, when a arrives at B, B is still 10 kilometers away from A. how many kilometers are there between the two places?
When meeting, the first line is 55 + 4 = 59, and the second line is 45 + 4. After meeting, the speed of the first line is 5 × (1-20%) = 4 = the speed of the second line, 10 ^ ((55 + 4 − 45 + 4) = 10 ^ (59-49), = 10 ^ 19, = 90 (km). A: the distance between the two places is 90 km
A and B start from ab at the same time and go in opposite directions. At the beginning of departure, the speed ratio of a and B is 5:4. After meeting, car a speeds up by 20%, while car B speeds up by 20%
Speed up by 30%, so when car a reaches B, car B is still 9.2 kilometers away from A. how many kilometers are there between AB and a?
When the speed of a is 1 + 20% = 6 / 5 and the speed of B is 4 / 5 × (1 + 30%) = 26 / 25, the speed ratio of a and B is 6 / 5:26 / 25 = 15:13 and the speed ratio of a and B is 4 / (4 + 5) = 4 / 9, the speed ratio of B is 4 / 9 × 13 / 15 = 52 / 135
Do vehicles a and B start from a and B at the same time? They are facing each other. After 1.5 hours, they meet 18 kilometers from the midpoint. It is known that the speed of vehicle a is the same as that of vehicle B
1.2 times, how many kilometers did the two cars travel when they met? (solved by equation)
Let B be x, then a is 1.2x, then 1.5 (1.2x-x) = 36, then x = 120, a is 1.2 * 120 * 1.5 = 216 km, B is 1.5 * 120 = 180 km
The speed ratio of the two vehicles is 4:3. After 5 hours, the two vehicles meet at a distance of 70 km from the midpoint. When they meet, the first line will stop
A's speed 4x B's 3x
4Xx5 = 3Xx5+70x2
5X=140
X=28
A 28x4 = 112
B 28x3 = 84
A left 112x5 = 560
B left 84X5 = 420
560 + 420 = 980
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