The distance between a and B is 639km. A passenger car and a freight car depart from the two places at the same time, facing two lines. It is known that the freight car travels 45km per hour, and the speed of the passenger car is the same as that of the freight car The speed of the bus is 1.2 times that of the truck. How many hours after the bus leaves, will the two cars meet?

The distance between a and B is 639km. A passenger car and a freight car depart from the two places at the same time, facing two lines. It is known that the freight car travels 45km per hour, and the speed of the passenger car is the same as that of the freight car The speed of the bus is 1.2 times that of the truck. How many hours after the bus leaves, will the two cars meet?


It takes x hours
therefore
45x+45×1.2x=639
45x+54x=639
99x=639
x≈6.45
It takes 6.45 hours



A and B start from two places at the same time. A travels 120 kilometers per hour and B travels 100 kilometers per hour. The distance ratio between them when they meet is (): ()
The time ratio for each of them to complete the journey is (): ()


A and B start from two places at the same time. A travels 120 kilometers per hour, B travels 100 kilometers per hour. The distance ratio when they meet (6): (5)
The time ratio for each of them to complete the journey is (5): (6)



Car a and car B leave from city a and city B respectively. Car a travels 36km per hour. The two cars meet 4 hours later. When they meet, how far does car a and car B travel
The ratio is 6:5


The same time, speed ratio = distance ratio = 6:5
So car B runs 36 △ 6 × 5 = 30 km per hour
Have a good time



Party A and Party B are walking towards each other from AB, 36km away. If Party A goes 2 hours ahead of Party B, they will meet after 2.5 hours of Party B's departure. If Party B goes 2 hours ahead of Party A, they will meet after 3 hours of Party A's advance and ask for the speed (process) of Party A and Party B to help


Let a speed be XKM / h and B speed be YKM / h
4.5x+2.5y=36,①
3x+5y=36.②
①-②,1.5x-2.5y=0,y=3x/5,③
Substituting 3 into 2, 6x = 36, x = 6,
3, y = 3.6