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A and B set out at the same time from two places 36km apart, and they meet each other after 4 hours and 30 minutes. If B walks for 2 hours first, then a sets out again, a will meet B after 3 hours and 40 minutes, and then find out the speed of a and B
The ratio of speed to time is 3 hours 40 minutes = 11 / 3 hours
A: B = (2 + 11 / 3-4.5): (4.5-11 / 3) = 7:5
The speed of a is 36 △ 4.5X7 / (7 + 5) = 5.25 km / h
B's speed is 5.25x5/7 = 3.75km/h
It is known that Party A and Party B travel from two places 36km apart and meet in 1.8h. If Party A goes 2 / 3H ahead of Party B, then Party A and Party B meet after 2 / 3h of Party B's departure. Ask the speed of Party A and Party B
How to calculate
Let a be x km / h and B be y km / h
1.8*(x+y)=36
(3/2+3/2)x+(3/2)y=36
The solution is x = 4, y = 16
A: the speed of a is 4 km / h, and that of B is 16 km / h
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