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The distance between station a and station B is 520 kilometers. Car a travels 80 kilometers per hour, while car B travels 60 kilometers per hour. The two cars leave from station a and station B at the same time and go opposite each other. After the two cars leave for a period of time, car a stops for 30 minutes for some reason, and then goes on to meet with Party B. how many hours did car B walk when they met? (use the equation)
30 minutes = 0.5 hours
This problem is equivalent to that B starts for 0.5 hours first, and then a starts again
80（X-0.5）+60X=520
140X-40=520
140X=560
X=4
A and B leave from a and B at the same time & cedil; a travels 80 kilometers per hour, B travels 80 kilometers per hour
Car a and car B leave from a and B at the same time. Car a travels 80 kilometers per hour. The ratio of the distance traveled by car B to the whole journey is 1 ∶ 15. When they meet, the ratio of the distance traveled by car a and car B is 5 ∶ 4. How many kilometers are there between a and B
The ratio of the distance traveled by car B per hour to the whole journey is 1 ∶ 15. When car B travels 1 / 15 per hour, the ratio of the distance traveled by car a and car B is 5 ∶ 4. When car B meets, the distance traveled by car B is 4 / (5 + 4) = 4 / 9. When car a meets, the distance traveled by car a is 5 / (5 + 4) = 5 / 9. The time taken for car B to travel 4 / 9 is 4 / 9 △ 1 / 15 = 20 / 3. When car a meets, the distance traveled by car B is 4 / (5 + 4) = 4 / 9
The distance between station a and station B is 448 kilometers. A local train starts from station a, 60 kilometers per hour, and an express train starts from station B, 80 kilometers per hour. What's the matter
1. The two cars leave at the same time and go in opposite directions. How many hours after departure do they meet? 2. The two trains are facing each other. The slow train will drive for 28 minutes first. How many hours will the fast train meet?
1. If we meet at x hours after departure, then 60x + 80x = 448 and x = 3.2
2. Suppose that the express trains meet at x hours after departure, then 60 * (28 / 60) + 60x + 80x = 448 and x = 3
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