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On the same road, Xiaoming rides in the same direction as Xiaoguang. Xiaoming's speed is three times faster than Xiaoguang's. every 10 minutes a bus overtakes Xiaoguang, and every 20 minutes a bus overtakes Xiaoming. If a bus leaves at the same time from the departure station, then the distance between two adjacent buses is shorter______ Points
Suppose the interval of each bus is 1, then according to the meaning of the question, we can get the speed difference between the bus and Xiaoguang is: 1 △ 10 = 110, the speed difference between the bus and Xiaoming is: 1 △ 20 = 120, because Xiaoming's cycling speed is three times of Xiaoguang's speed, so Xiaoguang's speed is: (110-120) △ 2 = 140, then the bus speed is 140 + 110 = 18, 1 △ 18 = 1 × 8 = 8 (minutes), answer: every 8 minutes Send a car. So the answer is: 8
On the same road, Xiaoming rides a motorcycle in the same direction as Xiaoguang. Xiaoming rides four times faster than Xiaoguang
Every 12 minutes, a bus overtakes Xiaoguang, and every 30 minutes, a bus overtakes Xiaoming. It is known that a bus departs from the departure station at the same time interval. Question: how many minutes is the interval between two adjacent buses?
If the light speed is x, the bus speed is Z at 4x interval y
It is concluded that x * 12 / 60 = y * 12 / 60 + (x * 12 / 60)
4X*30/60=Y*30/60+(4X*30/60)
It's a mess. I have to think about it before I can come up with the formula
On a map with a scale of 1:500000, the distance between a and B is 4cm
How many centimeters should be drawn?
4 × 500000 = 20 km 2000000 △ 2000000 = 1
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