What is meant by "driving motor vehicles on roads other than expressways and urban expressways without following the prescribed lanes" What are the circumstances of such violation? I hope I can get a specific answer, because I just got punished and I can't remember where I broke the rules

What is meant by "driving motor vehicles on roads other than expressways and urban expressways without following the prescribed lanes" What are the circumstances of such violation? I hope I can get a specific answer, because I just got punished and I can't remember where I broke the rules


In addition to highways, urban expressways outside the road violations
For example, turning on the straight road; straight on the turning road; pressing the line, etc



On the highway, a 3.5-meter-long car is driving at 45 meters per second, and a large truck is driving at 35 meters per second, with a length of 16.5 meters in front
On the highway, a 3.5-meter-long car is driving at the speed of 45 meters per second, and a 16.5-meter-long truck is driving in the same direction at the speed of 35 meters per second. What is the overtaking time for the car to catch up with the truck? The solution of the one variable linear equation


Solution x seconds car catch up with the truck
35x+3.5+16.5=45x
Finally, x = 2
Answer: 2 seconds car catch up with truck



A car with a length of 3.5 meters is driving at a speed of 45 meters per second, and a large truck with a length of 16.5 meters is driving in the same direction at a speed of 35 meters per second. From the time when the front of the small car is flush with the rear of the large truck, how long does it take for the car to completely surpass the large truck?


The distance difference between two cars is 3.5 + 16.5 = 20m when fully overtaking
Then time = 20 / (45-35) = 20 / 10 = 2 seconds



A small car is 3.5 meters long and runs at a speed of 45 meters per second. A 16.5-meter truck in front runs in the same direction at 35 meters per second. It takes more time for the small car to overtake the big car


L1=3.5m,v1=45m/s,L2=16.5m,v2=35m/s
Taking the freight car as the reference, the relative speed of the car: V '= V1-V2 = 45-35 = 10
Overtaking time: T = (L2 + L1) / V '= (16.5 + 3.5) / 10 = 2S