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When a car runs along a straight road, it first passes through the first 3 / 1 displacement at speed V1, and then passes through the other 2 / 3 displacement at speed V2 = 50km / h, If the average velocity of the whole displacement is 37.5km/h, what is the velocity in the first displacement thank you Wrong number on the top. It's 1 / 3 displacement
If we take the whole displacement as 1, then they use the same time, that is to say
(1 / 3) / V1 + (2 / 3) / V2 = 1 / VA, just substitute the variables into the solution, and the answer is 25km / h
When car B reaches the midpoint in four hours, car a is still 50 km away. Car a's speed is four fifths of car B's. how long is the road
Set the length of the road as XKM and the speed of vehicle B as YKM / h
Lie equation: X / 4: y = 5:4 (1)
X-4Y=50 (2)
The solution of the equation is x = 250, y = 50
A: how long is the road? 250km
How much resistance does a car suffer when driving at a speed of 100km / h on a 50km highway at a uniform speed
It can only be calculated by providing the drag coefficient of the car
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