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The speed of car a and car B are 52 km and 40 km per hour respectively. At the same time, from a to B, car a meets car 7 hours after departure, and car B also meets car 1 hour later
This is the problem of meeting, and its equivalent is the distance setting speed K, (52 + k) * 7 = (40 + k) * 8, k = 44km / h
A walks from a to B at a speed of 6 km / h. After 40 minutes, B pursues a from a at a speed of 8 km / h
Results the distance between a and B was 5 kilometers
40 minutes = 2 / 3 hours. After a walks 6 × 2 / 3 = 4 (km), B starts to chase. The speed difference is 8-6 = 2 (km / h) and 4 △ 2 = 2 (H). They have walked 2 × 8 = 16 (km) and are still 5 km away from B. therefore, the distance between AB and ab is 16 + 5 = 21 (km) and the comprehensive formula is 6 × 40 / 60 △ 8-6
The speed of car a is 50 km / h, and that of car B is 40 km / h. when car a drives over 13-50 km from a and B, it meets with car B______ Kilometers
A: the distance between a and B is 225 km, so the answer is: 225
A and B drive from ab station to ab station at the same time, a car travels 40 kilometers per hour, B car's speed is 5 kilometers faster than a car, 3 hours, the distance between the two cars is 18 kilometers
How many kilometers is the distance between the two stations?
Car a travels 40 kilometers per hour
B car 40 + 5 = 45 km per hour
In the first case, the two vehicles did not meet, and the distance between them was 18 km
Distance between two stations: (40 + 45) X3 + 18 = 273 (km)
The second situation: after the two cars meet, the distance between them is 18 km
Distance between two stations:: (40 + 45) x3-18 = 237 (km)
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