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No.1 and No.2 buses leave from the starting station at 6:00 in the morning. No.1 bus leaves every 6 minutes, and No.2 bus leaves every 9 minutes After these two buses start at the same time, how many minutes will they start at the same time?
Meet every 18 minutes, take the least common multiple of 6 and 9
No.3 bus leaves every 6 minutes, and No.5 bus leaves every 8 minutes. After the two buses leave at the same time, the two buses can run again at least a few minutes
At the same time?
No.3 bus leaves every 6 minutes, No.5 bus leaves every 8 minutes
"After the two buses start at the same time, the two buses can start at the same time at least a few minutes"
That is to find the least common multiple of the interval time
That is to find the least common multiple of 6 minutes and 8 minutes
The least common multiple is 24 minutes
So: at least 24 minutes, two cars can start at the same time
Huanbei market is the starting point of No.3 bus and No.5 bus. No.3 bus leaves every 5 minutes, No.5 bus leaves every 8 minutes, and No.2 bus leaves at 6 am
Huanbei market is the starting point of No.3 bus and No.5 bus. No.3 bus leaves every five minutes, No.5 bus leaves every eight minutes, and No.2 bus leaves at the same time at 6 am. At least how many minutes will the No.2 bus leave at the same time?
Because the least common multiple of 5 and 8 is 40,
So after at least 40 minutes, the two buses will start at the same time
The starting point of No.1, No.2 and No.3 bus at a bus stop starts at 6 a.m., and No.1 bus leaves every 6 minutes, No.2 bus leaves every 9 minutes, and No.3 bus leaves every 8 minutes. When and when is the second time?
The least common multiple of 6,9 and 8: 72
72 minutes = 1 hour 12 minutes
6:00 plus 1 hour and 12 minutes = 7:12
A: the second departure at the same time is at 7:12
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