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The top of a trapezoid is three times as big as the bottom. If the bottom is extended by 6 cm, it will become a parallelogram. How many cm are the top and bottom of the trapezoid?
Bottom = 6 △ 3-1 = 3 (CM)
Top and bottom = 3 × 3 = 9 (CM)
The top of a trapezoid is three times the bottom. If the bottom is extended by 6 cm, it will become a parallelogram. The top and bottom of the trapezoid are () cm each
Bottom: 6 / (3-1) = 3cm
Upper sole: 6 / (1-1 / 3) = 9 cm
After the top and bottom of a trapezoid are extended by 5 cm, it becomes a parallelogram, with an area of 15 square cm larger than the original,
Known that the original trapezoid bottom is 8 cm, the trapezoid area
Let the height of the triangle be x (that is, the height of the ladder is x), and we get 5x / 2 = 15, x = 6. So the height of the trapezoid is 6, because the upper and bottom are 8-5 = 3, so the trapezoid area is (3 + 8) * 6 / 2 = 33
A trapezoidal land is 40 meters at the top and 60 meters at the bottom. The area of this land is 1500 square meters. What is its height
1500x2 ÷ (40 + 60) = 30m
As shown in the figure, the side BC of parallelogram ABCD is 10 cm long, and the right side EC of right triangle ECB is 8 cm long. The total area of known shadow part is 10 cm 2 larger than that of triangle EFG. Calculate the area of parallelogram ABCD
A: the area of parallelogram ABCD is 50 square centimeter
The base and area of a triangle and a parallelogram are equal respectively. The area of a triangle is 18 square centimeters and the height is 3.6 centimeters. Find the height of a parallelogram
The base and area of a triangle and a parallelogram are equal, so the height of a triangle is twice that of a parallelogram
The height of a parallelogram is half that of a triangle
Height of parallelogram = 3.6 △ 2 = 1.8 cm
The base and area of a triangle are equal to those of a parallelogram. The height of parallelogram is 10cm, and the height of triangle is ()
A. 10cmB. 20cmC. 5crn
Let the height of triangle be H1, the height of parallelogram be H2, because H1 = 2S △ a, h2 = s △ a, so h2 = 12h1, so the height of triangle is twice that of parallelogram, and the height of triangle is: 10 × 2 = 20 (CM)
The base and area of a triangle and a parallelogram are respectively equal. The area of the triangle is 14 square centimeters and the height is 2.8 centimeters. This parallelogram
What's the height of the car
What's the formula
Because the triangle has an area of 14 square centimeters and a height of 2.8 centimeters,
So the length of the base of the triangle is: 14 × 2 △ 2.8 = 10 cm
So the height of the parallelogram is 14 △ 10 = 1.4cm
The base and area of a triangle are equal to those of a parallelogram. The height of parallelogram is 10cm, and the height of triangle is ()
A. 10cmB. 20cmC. 5crn
Let the height of triangle be H1, the height of parallelogram be H2, because H1 = 2S △ a, h2 = s △ a, so h2 = 12h1, so the height of triangle is twice that of parallelogram, and the height of triangle is: 10 × 2 = 20 (CM)
A triangle is equal to a parallelogram in height. It is known that the area of the parallelogram is 25.5 square meters larger than that of the triangle
Urgent 11!
We need the formula!
The area of parallelograms and triangles of equal height is twice that of triangles. The area of parallelograms is twice that of triangles. The area of parallelograms is 25.5 square meters. The area of triangles is 25.5 square meters. The area of parallelograms is 51 square meters
Let the triangle area be x and the parallelogram area be 2x,
2X-X=25.5
X=25.5
The area of parallelogram is 2x = 2 * 25.5 = 51 square meters
The area of the triangle is 25.5 square meters
RELATED INFORMATIONS
- 1. The area of a parallelogram is 86 square meters, which is the same as the area of a triangle with the same base and height______ ．
- 2. The side length of square ABCD is 12, e is a point on BC and be = 5, the vertical bisector Mn of AE intersects CD at point m and ab at point n, and the length of Mn is calculated
- 3. Known: as shown in the figure, in square ABCD, points E.M and N are on the sides of AB, BC and ad respectively, CE = Mn, ∠ MCE = 35 degrees, find the degree of ∠ anm
- 4. The length of square ABCD is 4, M is the moving point on BC, n is the moving point on CD, am is perpendicular to Mn, BM =? ABCN has the largest area
- 5. As shown in the figure, the rectangle ABCD is folded along AE so that point d falls at point F on the edge of BC. If ∠ BAF = 60 °, then ∠ DAE=______ Degree
- 6. As shown in the figure, in diamond ABCD, point E is on BC, and AE = ad, ∠ ead = 2 ∠ BAE, find the degree of ∠ BAE
- 7. It is known that e is the middle point on the side BC of square ABCD, f is a point on CD, AE bisects ∠ BAF
- 8. Known: as shown in the figure, in square ABCD, e is the midpoint of BC, point F is on CD, angle FAE is equal to angle BAE, AF = BC + EC
- 9. The side length of a diamond is 5, and a diagonal line is 6. Now take the straight line where the two diagonal lines are as the coordinate axis to find the four vertices
- 10. In the rectangular trapezoid ABCD, AD / / BC, ∠ a = 90 ° ad = 21cm BC = 24cm E.F. moves from A.C. to D.B. at the same time at 1cm / s and 2cm / s. when they move for how long, is the trapezoid efcd a rectangular trapezoid?
- 11. The height of a trapezoid is 10 cm. If the upper bottom is increased by 6 cm and the lower bottom is increased by 4 cm, it becomes a parallelogram. Calculate the area of the original trapezoid
- 12. As shown in the figure, a, B, C and D are the four vertices of rectangle ABCD, ab = 25cm and ad = 8cm. The moving points P and Q start from point a and C at the same time. Point P moves to point B at the speed of 3cm / s until point B, and point Q moves to point d at the speed of 2cm / S. (1) P and Q, from the start to the second, PQ ‖ ad? (2) Question: P, Q two points, from the start to a few seconds, quadrilateral pbcq area of 84 square centimeters?
- 13. As shown in the figure, in the known trapezoidal ABCD, ad ‖ BC, ∠ B = 30 °, C = 60 °, ad = 4, ab = 33, then the length of the bottom BC is______ ．
- 14. In the right angle trapezoid ABCD, AD / / BC, ∠ B = 90 °, ad = 24cm, BC = 26cm, the moving point P moves rapidly from a along the side of ad to D at the speed of 1cm per second In the right angle trapezoid ABCD, AD / / BC, ∠ B = 90 °, ad = 24cm, BC = 26cm, the moving point P starts from a and moves at the speed of 1cm / s along the ad side to D, the moving point Q starts from point C and moves at the speed of 3cm / s along the CB side to B, and P and Q start from points a and C at the same time. When one point reaches the end point, the other point also stops moving?
- 15. As shown in the figure, in the diamond ABCD, ab = 2, ∠ C = 60 °, the diamond ABCD rolls to the right on the straight line l without sliding. Each rotation of 60 ° around a vertex is called an operation. After 36 such operations, the total length of the path that the diamond center o passes through is (the result retains π)______ ．
- 16. The ratio of the top to the bottom of a trapezoid is 3:5. The top is 1 meter shorter than the bottom, and the bottom is 25% higher. The area of the trapezoid is ()
- 17. As shown in the figure, in rectangular ABCD, e is a point on CD, angle DEA = 30 degrees, and AE = AB = 8cm, find 1, degree of angle EBC, 2, area of triangle Abe
- 18. It is known that, as shown in the figure, P is a point in the square ABCD, and there is a point e outside the square ABCD, satisfying the angle Abe = angle CBP, be = BP 2.PB⊥BE.
- 19. As shown in the figure, in the square ABCD, ab = 1, point P is a point on the diagonal AC, and AP and PC are used as the diagonal to make the square respectively, then the sum of the perimeter of the two small squares is______ ．
- 20. In square ABCD, point E.F is on edge BC and CD respectively. If AE = 4, EF = 3 and AF = 5, what is the area of square ABCD