If the perimeter of parallelogram is 48mm and the diagonal intersects o, the perimeter of triangle AOB is 4mm longer than that of triangle BOC, then the lengths of AB and BC are equal to?

Let AB = x, BC = y. then 2 (x + y) = 48, X-Y = 4. Note: ((AB + Bo + OA) - (BC + CO + Bo) = ab-bc)
So x = 14, y = 10

The perimeter of the parallelogram ABCD is 80cm, and the diagonal AC and BD intersect at point O. if the perimeter of the triangle OAB is 8cm less than that of the triangle OBC, the length of AB is calculated
The parallelogram ABCD is 80cm, and the perimeter of triangle OAB is 8cm less than that of triangle OBC

After drawing, we can see that:
The perimeter of △ OAB = OA + ob + AB, the perimeter of △ OBC = ob + OC + BC, and because the diagonals of parallelogram ABCD are equally divided, that is, OA = OC, the perimeter of △ OBC - the perimeter of △ OAB = bc-ab = 8cm
Let AB be xcm, then BC be (x + 8) cm
The perimeter of parallelogram ABCD = 2 (AB + BC) = 80cm
The equation is: 2 (x + X + 8) = 80
So: x = 16
The length of AB is 16cm

The perimeter of the parallelogram is 80cm, and the diagonal lines AC and BD intersect at point O. if the perimeter of the triangle OAB is 8cm less than that of the triangle OBC, the length of AB is calculated
I'll have it today

The perimeter of parallelogram is 80, which means AB + BC = 40;
The perimeter of OAB is 8 less than that of OBC, which means bc-ab = 8;
The solution is ab = 16, (BC = 24)

It is known that the perimeter of the parallelogram ABCD is 50 cm, the perimeter of △ ABC is 35 cm, and the length of the diagonal AC is ()
A. 5cm B. 10cm C. 15cm D. 20cm

The ∵ quadrilateral ABCD is a parallelogram, ∵ AB = DC, ad = BC, ∵ ABCD's perimeter is 50cm, ∵ AB + BC = 50 △ 2 = 25 (CM), ∵ ABC's perimeter is 35cm, ∵ AC = 35-25 = 10cm

If the perimeter of parallelogram is 48mm and the diagonal intersects o, the perimeter of triangle AOB is 4mm longer than that of triangle BOC, then the lengths of AB and BC are equal to?