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1. Make a cuboid with six small cubes whose edges are 2cm long. The surface area of the cuboid is () CM & # 178;, and the volume is () CM & # 179 2. In a rectangle, draw a line segment and divide it into a maximum isosceles right triangle and a trapezoid
1. Make a cuboid with six small cubes whose edges are 2cm long. The surface area of the cuboid is (104 or 88) CM & # 178;, and the volume is (48) CM & # 179
2. In a rectangle, draw a line segment and divide it into a largest isosceles right triangle and a trapezoid
Use a compass to take the width of the length of the point, a line will become
A cuboid, with a cube at the bottom, is 12cm high, and the sum of the lengths of all edges is 112cm. What is the surface area and volume of the cuboid?
The length of each edge on the bottom = (112-4 * 12) / 8 = 8 cm
Surface area = 2 * 8 * 8 + 4 * 8 * 12 = 512 square centimeter
Volume = 8 * 8 * 12 = 768 CC
Divide the cube with 12cm edge length into three identical cuboids. What is the surface area and volume of each cuboid?
A simple drawing shows that the length, width and height of each cuboid are 12cm, 4cm and 12cm respectively
Through the surface area formula of cuboid: (length × width + length × height + width × height) × 2
Cuboid volume formula: length × width × height
You can calculate the surface area and volume of each cuboid
The answer is: surface area: 480cm & # 178;; volume: 576cm & # 179
RELATED INFORMATIONS
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