When object a weighing 1.5n is still in water in a cylindrical container with a bottom area of 100cm2 When the object a weighing 1.5n is still in the water of a cylindrical container with a bottom area of 100cm2, 2 / 5 of the volume of the object is exposed on the water surface, and the depth of the water is 10cm. If an object B is placed on the object a, they are just suspended in the water, and the pressure of the water on the bottom of the container is 1200pa Ask for: (1) The density of object a; (2) The density of object B

When object a weighing 1.5n is still in water in a cylindrical container with a bottom area of 100cm2 When the object a weighing 1.5n is still in the water of a cylindrical container with a bottom area of 100cm2, 2 / 5 of the volume of the object is exposed on the water surface, and the depth of the water is 10cm. If an object B is placed on the object a, they are just suspended in the water, and the pressure of the water on the bottom of the container is 1200pa Ask for: (1) The density of object a; (2) The density of object B




As shown in the figure, on the horizontal table, there are two cylindrical containers a and B, with the bottom areas of 80 & nbsp; cm2 and 100 & nbsp; cm2 respectively. The container a is full of water, and the container B is empty. If all the water in a is poured into B, the water level in B is 8 & nbsp; cm lower than that of A. what is the volume of a?


Suppose the volume of a is x, then the height of a is: (x △ 80) cm, and the height of B is: (x △ 100) cm. According to the equivalent relationship in the question, the equation can be listed: (x △ 80) - (x △ 100) = 8, and the solution is: x = 3200, so the volume of a is 3200cm2



The closed container full of water is placed on the horizontal table, and the ratio of the upper and lower bottom area is 4:1. At this time, the pressure of water on the bottom of the container is f, and the pressure is p
Why don't we use f = g = mg,


It must be different. If you hold the tip of the cone in your hand, or if you hold the bottom of the cone in your hand, it's related to the area under force