Five cubes with 1cm sides are put together to ask about the surface area and volume of the figure (four below and one above) □ □□□□ (my one is more separate. It should be more neat! But that's what the graphics are like.)

Five cubes with 1cm sides are put together to ask about the surface area and volume of the figure (four below and one above) □ □□□□ (my one is more separate. It should be more neat! But that's what the graphics are like.)

One cube is 1, five volumes are 5cm ^ 3
The surface area of a cube is 6, 5 should be 30, but it needs to subtract 8 faces, so the surface area is 22cm ^ 2

In the center of the top of a large cube with 3 cm edge length, dig out a small cube with 1 cm edge length, and calculate the current surface area and volume

3 × 3 × 6 = 9 × 6, = 54 (square centimeter), 1 × 1 × 4 = 4 (square centimeter), 54 + 4 = 58 (square centimeter); 3 × 3-1 × 1 × 1, = 27-1, = 26 (cubic centimeter)

The length, width and height of a cuboid are 6cm, 5cm and 4cm respectively. If it is cut into three cuboids of equal volume, what is the maximum sum of the surface area of the three cuboids?

The surface area of the original cuboid: (6 × 5 + 6 × 4 × 5 × 4) × 2, = (30 + 24 + 20) × 2, = 74 × 2, = 148 (square centimeter), the increased area: 5 × 6 × 4 = 120 (square centimeter), the maximum sum of the surface areas is 148 + 120 = 268 (square centimeter); a: the maximum sum of the surface products of the three cuboids is 268 square centimeter