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A cuboid with a length of 6dm, a width of 5DM and a height of 4dm is divided into three identical cuboids. The sum of the surface areas of the three cuboids is larger than that of the original cuboid How many square decimeters can be increased at most?
Maximum increase = 4 × 6 × 5 = 120 square decimeters
Cut a cube with a surface area of 7.2 square decimeters into three small cuboids of the same size. How many square decimeters is the surface area of each cuboid?
Each face: 7.2 △ 6 = 1.2 (square decimeter)
Surface area of each cuboid: (1.2 × 4 + 7.2) △ 3 = 4 (square decimeter)
The answer is 4 square decimeters!
Divide a cuboid 7 decimeters long, 6 decimeters wide and 5 decimeters high into exactly the same three cuboids. The surface area of this cuboid is larger than that of the original cuboid
Divide a cuboid 7 decimeters long, 6 decimeters wide and 5 decimeters high into exactly the same three cuboids. How much does the surface area of this cuboid increase more than that of the original cuboid
There are three cases
(1) Horizontal segmentation
Add four 7 × 6 surfaces: 4 × 7 × 6 = 168 square decimeters
(2) Vertical division (slitting)
Add four 5 × 6 surfaces: 4 × 5 × 6 = 120 square decimeters
(3) Vertical split (crosscut)
Add four 5 × 7 surfaces: 4 × 5 × 7 = 140 square decimeters
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