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As shown in the picture, in a piece of square paper with a side length of 10 cm, cut out a square with a length of 6 cm and a width of 4 cm. What is the area of the remaining part? What's the perimeter of the rest?
(1) 10 × 10-6 × 4, = 100-24, = 76 (square centimeter); (2) 10 × 4 = 40 (centimeter); answer: the area of the remaining part is 76 square centimeter and the perimeter is 40 centimeter
5 pieces of square paper with side length of 10 cm are overlapped with each other as shown in the right figure. The perimeter of this figure is 120 cm. If 51 pieces of paper are overlapped in this way
Then the perimeter of the figure is ()
(10x4x5-120)/(5-1)x(51-1)
=(200-120)/4x50
=80/4x50
=1000 cm
A: the perimeter of the figure is 1000 cm
The bottom of a rectangle is a square with a side length of 20 cm and a height of 40 cm. If you increase its height by 5 cm, how much will its area increase?
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A square with a side length of 20 cm has a circumference of 20 cm × 4 = 80 cm
The height increases by 5 cm and the surface area increases by 80 cm × 5 cm = 400 square cm
A: the area will be increased by 400 square centimeters,
This problem has nothing to do with the cuboid's total height of 40 cm
Good luck and goodbye
The area of a rectangle is 625 square centimeters. If the length of a rectangle is reduced by five times and the width is expanded by five times, it will become a square. How about the area of a square? How about the side length
This is very simple. The area is 625. Let's be more specific. Let's say that length x and width y, then the area is xy = 625. After the length is reduced by 5 times and the width is increased by 5 times, the area is unchanged and becomes a square. Then a ^ 2 = 625, that is, a = 25
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