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How to translate a positive scale function into a linear function, up and down or left and right? In addition, how does the analytic expression of the function change after the up-down translation and left-right translation of the positive proportion function? Thank you! It's urgent!
How to translate a positive proportion function into a function can be translated up and down or left and right
If the analytic expression of positive proportion function is y = KX, then
If you translate B units up, you get y = KX + B; if you translate B units down, you get y = kx-b,
If we translate B units to the left, we get y = K (x + b); if we translate B units to the right, we get y = K (X-B)
The translation law of first order function
Please help to sort out the law of up and down left and right translation of a function
The rule is left plus right minus and up plus down minus. For example, to move a unit length to the left is y = K (x + 1) + B, to move a unit length to the right is y = K (x-1) + B, to move up a unit length is y = kx + (B + 1) and to move down a unit length is y = KX + (B-1)
What's the procedure of a function image moving left and right? Give me an example,
A function of degree is a linear function
I don't know how to draw the image of the function itself
For translation, if y = f (x),
The function is y = f (x) + 2
Shift one unit to the left, and the function after shift is y = f (x) - 1
So if the original function adds x to shift x to the right and subtracts x to shift x to the left
There is a problem I don't quite understand: a function y = KX + B, moving n units up and down is B plus or minus n. but what's the rule of moving left and right?
Moving n units up and down means that the independent variable x remains unchanged, the function value y increases or decreases n, and the corresponding function becomes y = KX + B + N, y = KX + b-n
Moving n units left and right means that the value of the function remains unchanged, the independent variable x decreases and increases n, and the corresponding function becomes y = K (x + n) + B, y = K (x-n) + B
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