Given that the images of the linear functions y = - 4 / 1X + m and y = 4 / 3x + n pass through the point P (- 4,0) and intersect with the Y axis at M and N points respectively, the area of the triangle PMN is?

Given that the images of the linear functions y = - 4 / 1X + m and y = 4 / 3x + n pass through the point P (- 4,0) and intersect with the Y axis at M and N points respectively, the area of the triangle PMN is?

I guess it should be: linear functions y = - 1 / 4 * x + m and y = 3 / 4 * x + n
By substituting the point P (- 4,0), the solution is obtained
m=-1,n=-3
The linear equations are: y = - X / 4-1; y = 3x / 4-3
The intersections with Y-axis are m (0, - 1), n (0, - 3)
The area of ∧ PMN is
S=1/2*|MN|*|OP|
=1/2*2*4
=4

How to draw the function image of y = - 2 / 3x - 2

First draw the image of y = 1 / x, then draw the image of y = - 1 / x, and then the abscissa remains unchanged, and the ordinate becomes two-thirds of the original, so as to get this picture. Then move the whole picture two units to the left

What is the analytic expression of the symmetric image of the quadratic function y = x ^ 2-3x-4 about the Y axis? What is the analytic expression of the symmetric image about the X axis? What is the analytic expression of the image about the vertex rotated 180 degrees?

y = (x-3/2)^2 - 25/4
y = (x+3/2)^2 - 25/4 = x^2+3x -4
Y = - x ^ 2 + 3x + 4 (negative of original y)
Y = - x ^ 2 & nbsp; + 3x - 8.5

The coordinate of the point of intersection of the image of quadratic function y = x2-3x and X axis about the origin

By solving the equation x & # 178; - 3x = 0, we get X1 = 0, X2 = 3
The point of intersection with X axis is (0,0), (3,0)
The coordinates of the symmetric point about the origin are (0,0), (- 3,0)