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Given the image of the first-order function y = - 3x + 6, (1) x_ When y
Given the image of the first-order function y = - 3x + 6, (1) when x > 2, y
This paper points out the opening direction of the function y = 3x & # 178; + X-2 image, and finds out that when y ≥ 0, the value range of X is about to change
Opening up
3x²+x-2>=0
3 -2
1 1
(3x-2)(x+1)>=0
x> = 2 / 3 or X
RELATED INFORMATIONS
- 1. The graph and Y-axis of the linear functions y = (m-2) x + 1 and y = (m-1) x + M & # 178; - 5 intersect point P and point Q respectively. If point P and point q are symmetric about x-axis, the value of M is obtained
- 2. Given the linear function Y1 = - 3x-4 and y2 = 5x-20, when x takes what value, the function Y1 is not less than Y2?
- 3. Make the graph of the following function of degree. (1) y = 4x-2 (2) y = - X-1 (3) y = 3x / 2 + 2 (4) y = - x + 2
- 4. As shown in the figure, Y1 = | x |, y2 = 1 / 3 x + 4 / 3, when Y1 > Y2 The value range of X is (); The known functions are: ① y = 0.2x + 6; ② y = - X-7; ③ y = 4-2x; ④ y = - x; ⑤ y = 4x; ⑥ y = - (2-x), where the value of Y increases with the increase of X_____________ The function that the value of Y decreases with the increase of X is________________ The function of the image passing through the origin is_____________ (fill in serial number)
- 5. Point P is in the second quadrant, the distance from P to X axis is 4, and the distance from P to y axis is 3, then the coordinate of point P is
- 6. The intersection of the image with positive integer y = (- K / K + 1) x + (1 / K + 1) K and X, Y axes is a, B, and the origin is o. let the AOB area of RT triangle be SK, and find S1 + S2 + What is the value of s2009?
- 7. If the intersection of the image of the linear function y = - K / K + 1 x + 1 / K + 1 (k is a natural number) and the x-axis and y-axis is a, B.O. let the area of RT △ ABO be SK, then (1) find S1 (2) find S1 + S2 + S3 + +Value of s2010
- 8. It is known that the image with positive scale function y = KX passes through point a (x, 4), and O is the origin of the coordinate (1) If OA = 5, then X= (2) If the angle between OA and X axis is 60 degrees, then x= (1) The answer to this question is ± 3; the answer to this question is 4 / 3 × root 3
- 9. 1. When m satisfies (), the image of the first-order function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis Correction: 1. When m satisfies (), the image of the linear function y = 3x = M-4 intersects the y-axis on the negative half axis; when m satisfies (), the image of the function y = - 2x-m + 2 intersects the x-axis on the positive half axis What is the intersection of function = y = - 5x + 2 and X axis? What is the point of intersection with the y-axis? What is the area of the triangle enclosed by two coordinates?
- 10. Given that the images of the linear functions y = - 4 / 1X + m and y = 4 / 3x + n pass through the point P (- 4,0) and intersect with the Y axis at M and N points respectively, the area of the triangle PMN is?
- 11. Using the pointer to the function as the function parameter, find the piecewise function. When x < 0, y = x + 2; when 0 ≤ x < 5, y = 3x-1; when x ≥ 5, y = x (x-1)
- 12. Given the equation 3x-2y = 1, it is written that y is a first-order function of X
- 13. It is known that the intersection coordinates of the first-order function Y1 equal to 3x + 3 and Y2 equal to 2x + 8 in the same rectangular coordinate system are (1,6), then when Y1 is greater than Y2, the value range of X is (1,6)
- 14. Given that the image intersection point (- 1,5) of the linear function Y1 = 3x + A and y2 = - x + B, then when x satisfies what, Y1 = Y2
- 15. Given the linear function Y1 = - x + 3 and y2 = 3x-1, when x takes what value, Y1 > Y2? Y1 = Y2? Y1
- 16. As shown in the figure, the images of inverse scale function Y1 = K1X and positive scale function y2 = k2x all pass through point a (- 1,2). If Y1 > Y2, then the value range of X is () A. - 1 ＜ x ＜ 0b. - 1 ＜ x ＜ 1C. X ＜ - 1 or 0 ＜ x ＜ 1D. - 1 ＜ x ＜ 0 or X ＞ 1
- 17. It is known that the three vertices of triangle ABC are all on the image of inverse scale function y = 1 / X. it is proved that its perpendicular center h is also on the image of this function
- 18. Given that the point C is the inverse scale function, the perpendicular foot of the vertical line drawn from the point C to the coordinate axis is ab, and the area of the quadrilateral aobc is 6, the analytic solution of the inverse scale function is obtained
- 19. Take point P on the image of linear function y = - x + 3, make PA perpendicular to X axis A, Pb perpendicular to y axis B, and the quadrilateral OAPB is a square, then the P coordinate
- 20. The point P is hyperbolic y = - 4 / X (x)