Take point P on the image of linear function y = - x + 3, make PA perpendicular to X axis A, Pb perpendicular to y axis B, and the quadrilateral OAPB is a square, then the P coordinate

Take point P on the image of linear function y = - x + 3, make PA perpendicular to X axis A, Pb perpendicular to y axis B, and the quadrilateral OAPB is a square, then the P coordinate

If we take point P on the image of the first-order function y = - x + 3 and make PA perpendicular to X axis A, Pb perpendicular to y axis B, and the quadrilateral OAPB is square, then
x=y
y=-x+3
So x = y = 3 / 2
At this point, the P coordinate (3 / 2,3 / 2)

It is known that P (m, 5) is a point on the inverse scale function y = K / x, PA ⊥ X axis, Pb is perpendicular to y axis, and s rectangle OAPB = 20
(1) Finding the value of M
(2) Point (a, b) is on hyperbola, and a + B = 12, find the value of a, B

(1) From | x | * | y | = 20, k = ± 20 is obtained, and y = 5 is substituted into M = ± 4;
(2) From the simultaneous solution of a + B = 12, ab = ± 20, the values of a and B are (2,10), (10,2), (6 + 2 √ 14,6-2 √ 14), (6-2 √ 14,6 + 2 √ 14)