Given that the image intersection point (- 1,5) of the linear function Y1 = 3x + A and y2 = - x + B, then when x satisfies what, Y1 = Y2

Given that the image intersection point (- 1,5) of the linear function Y1 = 3x + A and y2 = - x + B, then when x satisfies what, Y1 = Y2

From the meaning of the problem, we can see that the linear functions Y1 = 3x + A and y2 = - x + B both pass through the point (- 1,5)
Substituting x = - 1 and y = 5 into the function respectively, we can get a = 8 and B = 4
The simultaneous equations of Y 1 = 3x + 8, y 2 = - x + 4 and Y 1 = y 2 are obtained, and x = - 1 is the value of X

The intersection coordinates of the first-order function Y1 = 3x + 3 and y2 = - 2x + 8 in the same rectangular coordinate system are (1,6). Then when Y1 > Y2, the value range of X is (1,6)______ ．

The answer to this question is: x > 1

Given that the intersection coordinates of the first-order functions Y1 = 3x + A and y2 = - 2x + B in the same rectangular coordinate system are (1,6), then when Y1 > Y2, the value range of X is obtained

Substituting 1 6 into two equations to get AB, we can know that x > 1