The solution equation: TaNx - radical 3 = 0, X belongs to (- pie, pie)

The solution equation: TaNx - radical 3 = 0, X belongs to (- pie, pie)


X = faction / 3 + K faction because x belongs to (- faction, faction), so x = faction / 3 or - 2 faction / 3



If f (x) = logax, (a > 0 and a ≠ 1) satisfies f (9) = 2, then f (3)=______ .


From F (9) = 2, f (9) = loga9 = 2, that is, A2 = 9, and a > 0, so a = 3. Therefore, the answer is: 1



Given x ∈ (0,1 / 2), if loga (x) > x ^ 2 is constant, then the value range of A


This can use images
Draw the image c of y = x ^ 2 on (0,1 / 2),
It is necessary to ensure that the image of y = loga (x) is above image C
(1) A > 1, not satisfied
(2)0



It is known that two of the equations x ^ 2 - (log2 B + loga 2) x + loga B = 0 about X are - 1 and 2, and the values of real numbers a and B are obtained