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Derivative of y = x + 1 / X
1-1/x²
Derivative of y = x + 1 / X-1
y'=[(x+1)'(x-1)-(x-1)'(x+1)]/(x-1)²
=[(x-1)-(x+1)]/(x-1)²
=-2/(x-1)²
I see Baidu netizens' answers. I don't understand why [(x-1) '] and [(x + 1)'] should disappear. I haven't heard of this
This is actually the application of the sum difference derivative formula of function, because:
y=x-1
Then:
y'=(x)'-(1)'
=1-0
=1.
Finding the derivative of y = x / (x + 1)
y=x/(x+1)
y'=[(x+1)-x]/(x+1)^2
=1/(x+1)^2
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