Derivation f (x) = (e ^ (2x)) / (x ^ 2) + 1 process

This is the derivative of a composite function (U / V) '= (u'v-uv') / V ^ 2, so
f'(x)=[e^(2x)/(x^2)+1]'=[2e^(2X)*(X^2+1)-2X*e^(2X)]/(x^2+1)^2=e^(2x)*(2x^2-2x)/(x^2+1)^2