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這個是複合函數求導(u/v)'=(u'v-uv')/v^2,故 f'(x)=[e^(2x)/(x^2)+1]'=[2e^(2X)*(X^2+1)-2X*e^(2X)]/(x^2+1)^2=e^(2x)*(2x^2-2x)/(x^2+1)^2
f'(x)=3*x^2-3/(x^2)
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